Question

A woman walks due west on the deck of a ship at 4 mi/h. The ship is moving north at a speed of 20 mi/h. Find the speed and direction of the woman relative to the surface of the water. (Round your answers to one decimal place.)

Answer 1

Answer:

The speed of woman is 20.39 mi/h at and angle of 11.3 degrees wrt the surface of the water.

Explanation:

Given that,

Speed of women due west, $v_w=4\ mi/h$

Speed of women due north, $v_n=20\ mi/h$

We need to find the speed and direction of the woman relative to the surface of the water. The resultant speed is given by :

$v=\sqrt{v_w^2+v_n^2}$

$v=\sqrt{4^2+20^2}$

$v=20.39\ mi/h$

Let $\theta$ is the direction of speed. It is given by :

$\tan\theta=\dfrac{4}{20}$

$\theta=11.3^{\circ}$

So, the speed of woman is 20.39 mi/h at and angle of 11.3 degrees wrt the surface of the water.