Respuesta :

[tex]\dfrac{4z^{a+2}}{-8z^{a-2}}=-\dfrac{4}{8}z^{(a+2)-(a-2)}=-\dfrac{1}{2}z^{a+2-a+2}=\boxed{-\dfrac{1}{2}z^4}[/tex]

Answer:

its - - 1/2 z ^4

Step-by-step explanation: