changle. Show all work. Round each length to the nearest tenth and each angle to the
nearest degree.
17.
AC =
mZA =
mZC =

changle Show all work Round each length to the nearest tenth and each angle to the nearest degree 17 AC mZA mZC class=

Respuesta :

Answer:

Part 1) [tex]BC=12.2\ units[/tex]

Part 2) [tex]m\angle A=55^o[/tex]

Part 3) [tex]m\angle C=35^o[/tex]

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

[tex]AC^2=AB^2+BC^2[/tex]

substitute the given values

[tex]AC^2=7^2+10^2[/tex]

[tex]AC^2=149\\AC=12.2\ units[/tex]

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

[tex]tan(A)=\frac{BC}{AB}[/tex] ----> by TOA (opposite side divided by the adjacent side)

substitute the values

[tex]tan(A)=\frac{10}{7}[/tex]

using a calculator

[tex]m\angle A=tan^{-1}(\frac{10}{7})=55^o[/tex]

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

[tex]m\angle A+m\angle C=90^o[/tex] ----> by complementary angles

substitute the given value

[tex]55^o+m\angle C=90^o[/tex]

[tex]m\angle C=90^o-55^o=35^o[/tex]