Answer:
Part 1) [tex]BC=12.2\ units[/tex]
Part 2) [tex]m\angle A=55^o[/tex]
Part 3) [tex]m\angle C=35^o[/tex]
Step-by-step explanation:
Part 1) Find AC
we know that
In the right triangle ABC of the figure
Applying the Pythagorean Theorem
[tex]AC^2=AB^2+BC^2[/tex]
substitute the given values
[tex]AC^2=7^2+10^2[/tex]
[tex]AC^2=149\\AC=12.2\ units[/tex]
Part 2) Find the measure of angle A
we know that
In the right triangle ABC
[tex]tan(A)=\frac{BC}{AB}[/tex] ----> by TOA (opposite side divided by the adjacent side)
substitute the values
[tex]tan(A)=\frac{10}{7}[/tex]
using a calculator
[tex]m\angle A=tan^{-1}(\frac{10}{7})=55^o[/tex]
Part 3) Find the measure of angle C
we know that
In the right triangle ABC
[tex]m\angle A+m\angle C=90^o[/tex] ----> by complementary angles
substitute the given value
[tex]55^o+m\angle C=90^o[/tex]
[tex]m\angle C=90^o-55^o=35^o[/tex]