Step-by-step explanation:
Let the required line bisects the segment joining the point (5,3) and (4,4) at point M (x, y).
Therefore, M is the mid point of segment joining the point (5,3) and (4,4).
Now by mid-point formula we have:
[tex]M = ( \frac{5 + 4}{2} \: \: \frac{3 + 4}{2} ) = ( \frac{9}{2} \: \: \frac{7}{2} ) \\ \\ \therefore \: M \: = ( 4.5 \: \: 3.5 ) = (x_1 \: \: y_1)\\ \\ \because \: Line \: makes \: 45 \degree \: angle \: with \: positive \: \\ \: \: \: \: \: direction \: of \: x - axis. \\ \\ \therefore \: Slope \: of \: line: \: \\ \: \: \: \: \: \: \: m = tan \: 45 \degree = 1 \\ \\ Equation \: of \: line \: in \: slope \: point \: form\\ \: is \: given \: as: \\ y-y_1 =m(x-x_1) \\ \therefore \: y - 3.5 = 1(x - 4.5) \\ \therefore \: y - 3.5 = x - 4.5 \\ \therefore \: y = x - 4.5 + 3.5 \\ \therefore \: y = x - 1\\ \huge \purple { \boxed{\therefore \: x - y - 1 = 0}} \\ [/tex]
is the equation of required line.
