A string of fifty 15 ohm Christmas tree lights are connected in series. One burns out, they all burn out.Calculate the total resistance. (Draw a one way switch to control all of them at once)

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04-03-2020
Physics

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A string of fifty 15 ohm Christmas tree lights are connected in series. One burns out, they all burn out.Calculate the total resistance. (Draw a one way switch to control all of them at once)

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AL2006 AL2006 · Answer 1 · 2020-03-04T10:20:39+01:00

AL2006 AL2006

04-03-2020

The effective resistance of many individual resistors in series is the sum of the individual resistances.

50 items in series, each with a resistance of 15 ohms, are equivalent to a single resistance of (15 x 50) = 750 ohms.

By the way . . . If one of the little bulbs in series burns out, all the others do NOT burn out. They simply get turned off and go dark, because the current can't flow through the one that did.

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onyebuchinnaji onyebuchinnaji · Answer 2 · 2022-05-06T12:38:30+02:00

The total resistance of the string of fifty 15 ohm Christmas tree lights that are connected in series is 750 ohms.

Total resistance of the series resistors

The total resistance of the series resistors is determined by adding all the componenets of the resistors together.

Rt = R1 + R2 + R3 + ----

where;

Rt is the total resistance of the series circuit

Rt = 50 x (15 ohms)

Rt = 750 ohms

Thus, the total resistance of the string of fifty 15 ohm Christmas tree lights that are connected in series is 750 ohms.

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