Question

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Answer 1

Option C:

$\left(7 x^{2} y^{3}\right)\left(3 x^{5} y^{8}\right)=21 x^{7} y^{11}$

Solution:

Given expression is $\left(7 x^{2} y^{3}\right)\left(3 x^{5} y^{8}\right)$.

To find the product of the above expression.

$\left(7 x^{2} y^{3}\right)\left(3 x^{5} y^{8}\right)$

First multiply the numerical coefficients.

$\left(7 x^{2} y^{3}\right)\left(3 x^{5} y^{8}\right)=21 x^{2} y^{3} x^{5} y^{8}$

Arrange the terms with same base.

                         $=21 x^{2} x^{5} y^{3} y^{8}$      

Using exponent rule: $a^m \cdot a^n = a^{m+n}$

                        $=21 x^{2+5} y^{3+8}$

                        $=21 x^{7} y^{11}$

$\left(7 x^{2} y^{3}\right)\left(3 x^{5} y^{8}\right)=21 x^{7} y^{11}$

Hence option C is the correct answer.