Question

what is the position of the car at the end of the 10 secs?

Answer 1

Answer:

S=400m

Explanation:

Given t=10.and $a=8m/s^2$,

Initial velocity,$u$, of the car is zero.

To find distance,$s$

$S=ut+0.5at^2$

$S=0\times10+0.5\times8\times10^2\\S=400m$

Therefore, car's position after 10seconds is 400m away from the start.