Answer:
B
Step-by-step explanation:
I think this is your full question and hope it is correct.
Which system of equations could be graphed to solve the equation below?
log(2x+1)=3x-2
A. y1=3x, y2=2x
B. y1=log(2x+1), y2=3x-2
C. y1=log2x+1, y2=3x-2
D. y1=log(2x+1+2), y2=3x
My answer:
We know that: log(2x+1)=3x-2 and they are a equation of log and linear so we need to make system of equation.
The left side is: [tex]y_{1}[/tex] => [tex]y_{1} = log( 2x+1)[/tex]
The right side is : [tex]y_{2} = 3x -2[/tex]
The system of equations are:
[tex]\left \{ {{y_{1} =log(3x+1)} \atop {y_{2} =3x -2}} \right.[/tex]
Now we have two new function with x and y.
