Answer:
A and B are equally likely
Explanation:
The conditional probability is defined as follows:
[tex]P(X|Y)=\frac{P(X\cap Y)}{P(Y)}[/tex]
where:
[tex]P(X|Y)[/tex] is the probability for X to occur, given that Y has occurred
[tex]P(X\cap Y)[/tex] is the probability that both X and Y occur at the same time
[tex]P(Y)[/tex] is the probability for Y to occur
Given two events A and B, we have:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]
and
[tex]P(B|A)=\frac{P(A\cap B)}{P(A)}[/tex]
In this problem, we are told that
[tex]P(A|B)=P(B|A)[/tex]
Which means that:
[tex]\frac{P(A\cap B)}{P(B)}=\frac{P(A\cap B)}{P(A)}[/tex]
Simplifying, we get:
[tex]P(A)=P(B)[/tex]
which means that A and B are equally likely.