Respuesta :

Answer:

A and B are equally likely

Explanation:

The conditional probability is defined as follows:

[tex]P(X|Y)=\frac{P(X\cap Y)}{P(Y)}[/tex]

where:

[tex]P(X|Y)[/tex] is the probability for X to occur, given that Y has occurred

[tex]P(X\cap Y)[/tex] is the probability that both X and Y occur at the same time

[tex]P(Y)[/tex] is the probability for Y to occur

Given two events A and B, we have:

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]

and

[tex]P(B|A)=\frac{P(A\cap B)}{P(A)}[/tex]

In this problem, we are told that

[tex]P(A|B)=P(B|A)[/tex]

Which means that:

[tex]\frac{P(A\cap B)}{P(B)}=\frac{P(A\cap B)}{P(A)}[/tex]

Simplifying, we get:

[tex]P(A)=P(B)[/tex]

which means that A and B are equally likely.