Question

(3 plus 3 a )plus (1 plus 5 m )(3 plus 3 a )plus (1 plus 5 m )equals nothing ​(Simplify your​ answer.)

Answer 1

Answer:

$7+6a+5m(4+3a)=0$

Step-by-step explanation:

We want to simplify the expression

$(3 + 3 a ) + (1 + 5 m )(3 + 3 a ) + (1 + 5 m )=0$

Expanding the expression in the middle

$(3 + 3 a ) + 1 (3 + 3 a )+ 5 m (3 + 3 a ) + (1 + 5 m )=0$

Eliminating all brackets

$3 + 3 a + 3 + 3 a + 15m + 15m a + 1 + 5 m =0$

Next, we collect our like terms

$3+3+1+3a+3a+15m+5m+15ma=0$

When you collect like terms, ensure the number of terms are still the same

$7+6a+20m+15ma=0$

This simplified gives us:

$7+6a+5m(4+3a)=0$

Answer 2

I caculated it all and it is the same as Newton9022

Hope this helps.