In this exercise, we have the following function that result from a combination of two functions:
[tex]j(x) = -3x^2+5[/tex]
So the operations applies that could result in [tex]j(x)[/tex] are:
1. Two quadratic functions by addition:
For instance, it could be:
[tex]f(x)=-4x^2+3 \\ \\ g(x)=x^2+2 \\ \\ \\ j(x)=f(x)+g(x) \\ \\ j(x)=(-4x^2+3)+(x^2+2) \\ \\ j(x)=(-4x^2+x^2)+(3+2) \\ \\ j(x)=-3x^2+5[/tex]
2 linear function and a quadratic function by addition:
For instance, it could be:
[tex]f(x)=5 \\ \\ g(x)=-3x^2 \\ \\ \\ j(x)=f(x)+g(x) \\ \\ j(x)=5-3x^2\\ \\ j(x)=-3x^2+5[/tex]
Recall that a constant function like f(x) is also a linear function.
3. Two linear functions by multiplication
Applying a similar method we can conclude that the product of two linear functions will lead to the resulting function j(x). The product can be written as:
[tex]j(x)=f(x)g(x)[/tex]
Since both functions have degree 1, then when multiplying them we will get a maximum degree of 2.