Respuesta :
The solution of the system of equations is [tex]x=-2[/tex] and [tex]y=3[/tex]
Explanation:
The system of equations are [tex]4 x+5 y=7[/tex] and [tex]3 x-2 y=-12[/tex]
To determine the solution of the equation, let us solve the equations by elimination method.
Thus, multiplying the equation [tex]4 x+5 y=7[/tex] by 2, we get, [tex]8x+10y=14[/tex]
Multiplying the equation [tex]3 x-2 y=-12[/tex] by 5, we get, [tex]15x-10y=-60[/tex]
Adding these two equations, we have,
[tex]\ \ 8x+10y=14\\15x-10y=-60\\---------\\23x=-46[/tex]
Dividing both sides by 23, we have,
[tex]\frac{23x}{23} =\frac{46}{23}[/tex]
[tex]x=-2[/tex]
Thus, the value of x is [tex]x=-2[/tex]
Substituting [tex]x=-2[/tex] in the equation [tex]4 x+5 y=7[/tex], we get,
[tex]4 (-2)+5 y=7[/tex]
[tex]-8+5 y=7[/tex]
[tex]5y=15[/tex]
[tex]y=3[/tex]
Thus, the value of y is [tex]y=3[/tex]
Hence, the solution of the system of equations is [tex]x=-2[/tex] and [tex]y=3[/tex]
The solution to the system of equations, is: (-2, 3).
Solution to System of Equations
To find the solution, you can use the elimination method by first making both equations equivalent. Then add or subtract to eliminate a variable.
Given:
- 4x + 5y = 7 --> Eqn. 1
- 3x – 2y = –12 --> Eqn. 2
Multiply eqn. 1 by 3 and eqn. 2 by 4:
12x + 15y = 21 --> Eqn. 1
12x – 8y = –48 --> Eqn. 2
- Subtract:
23y = 69
- Divide both sides by 23
y = 3
Substitute y = 3 into eqn. 1.
4x + 5(3) = 7
4x + 15 = 7
4x = 7 - 15
4x = -8
x = -2
Therefore, the solution to the system of equations, is: (-2, 3).
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