Question

11. Simplify the complex fraction. n-4/n² - 2n-15/n +1/n +3

NEED HELP ASAP!!!!

Answer 1

Simplification of equation $\frac{n-4}{n^{2}} - \frac{2n-15}{n} + \frac{1}{n} +3$ is $1 + \frac{17}{n} - \frac{4}{n^{2}}$.

Step-by-step explanation:

We have the following complex fraction to simplify:

$\frac{n-4}{n^{2}} - \frac{2n-15}{n} + \frac{1}{n} +3$

⇒$\frac{n-4}{n^{2}} - \frac{2n-15}{n} + \frac{1}{n} +3$

{making denominator same of all expressions }

⇒$\frac{n-4}{n^{2}} - \frac{2n-15(n)}{n(n)} + \frac{1(n)}{n(n)} +\frac{3n^{2}}{n^{2}}$  

⇒ $\frac{n-4}{n^{2}} - \frac{2n^{2}-15n}{n^{2}} + \frac{n}{n^{2}} +\frac{3n^{2}}{n^{2}}$

⇒$\frac{n-4 -2n^{2} + 15n + n + 3n^{2}}{n^{2}}$

⇒ $\frac{n^{2}+17n-4}{n^{2}}$

⇒$1 + \frac{17}{n} - \frac{4}{n^{2}}$

∴ Simplification of equation $\frac{n-4}{n^{2}} - \frac{2n-15}{n} + \frac{1}{n} +3$ is $1 + \frac{17}{n} - \frac{4}{n^{2}}$.