Question

A person’s blood pressure is monitored by taking 3 readings daily. The probability distribution of his reading had a mean of 132 and a standard deviation of 5. Each observation behaves as a random sample. Find the mean of the sampling distribution of the sample mean for the three observations each day.

Answer 1

Answer:

The mean of the sampling distribution of the sample mean for the three observations each day is 132.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 132

Standard Deviation, σ = 5

Each observation behaves as a random sample.

a) Mean of the sampling distribution

$\bar{x} = \mu = 132$

b) Standard deviation of the sampling distribution

Sample size,n = 3

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{5}{\sqrt{3}} = 2.887$

Thus, the mean of the sampling distribution of the sample mean for the three observations each day is 132.