Question

If 50 liters of carbon dioxide gas are produced by the reaction below at 273 Kand 100 atm, how oxygen gas were used the reaction? 2 CO(g) + O2(g) ----> 2 CO2(g)

Answer 1

Using the ideal gas equation:

pV = nRT
n = pV / RT

1atm = 101325Pa, so p = 10132500Pa
1L = 0.001m^3, so V = 0.050m^3
R = 8.214 (ideal gas constant)
T = 273K

Hence moles of CO2 = (10132500 * 0.050) / (8.314 * 273) = 223.2101553

Reaction ratio between oxygen and CO2 is 1:2
Hence moles of O2 = 223... / 2 = 112 moles (3sf)