Solution:
Given that,
Gavin ran 10 MPH during Monday's workout
50% slower during Tuesday's workout
Therefore,
Speed in tuesday = 50 % slower than monday
Which means,
Speed in tuesday = 10 - 50 % of 10
Solve the above
[tex]\text{ Speed in tuesday } = 10 - \frac{50}{100} \times 10\\\\\text{ Speed in tuesday } = 10 - 0.5 \times 10\\\\\text{ Speed in tuesday } = 10 - 5\\\\\text{ Speed in tuesday } = 5\\\\[/tex]
Thus, he ran 5 mph in tuesday