Respuesta :

For this case we must indicate the solution set of the given inequalities:

[tex]-6x + 14 <-28[/tex]

Subtracting 14 from both sides of the inequality we have:

[tex]-6x <-28-14\\-6x <-42[/tex]

Dividing by 6 on both sides of the inequality:

[tex]-x <- \frac {42} {6}\\-x <-7[/tex]

We multiply by -1 on both sides, taking into account that the sense of inequality changes:

[tex]x> 7[/tex]

Thus, the solution is given by all values of x greater than 7.

On the other hand we have:

[tex]9x + 15 <-12[/tex]

Subtracting 15 from both sides of the inequality we have:

[tex]9x <-12-15\\9x <-27[/tex]

Dividing between 9 on both sides of the inequality we have:

[tex]x <- \frac {27} {9}\\x <-3[/tex]

Thus, the solution is given by all values of x less than -3.

Finally, the solution set is:

(-∞, - 3) U (7,∞)

Answer:

(-∞, - 3) U (7,∞)

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