For this case we must indicate the solution set of the given inequalities:
[tex]-6x + 14 <-28[/tex]
Subtracting 14 from both sides of the inequality we have:
[tex]-6x <-28-14\\-6x <-42[/tex]
Dividing by 6 on both sides of the inequality:
[tex]-x <- \frac {42} {6}\\-x <-7[/tex]
We multiply by -1 on both sides, taking into account that the sense of inequality changes:
[tex]x> 7[/tex]
Thus, the solution is given by all values of x greater than 7.
On the other hand we have:
[tex]9x + 15 <-12[/tex]
Subtracting 15 from both sides of the inequality we have:
[tex]9x <-12-15\\9x <-27[/tex]
Dividing between 9 on both sides of the inequality we have:
[tex]x <- \frac {27} {9}\\x <-3[/tex]
Thus, the solution is given by all values of x less than -3.
Finally, the solution set is:
(-∞, - 3) U (7,∞)
Answer:
(-∞, - 3) U (7,∞)