Respuesta :
Answer:
0.050 m LiBrm LiBr < 0.120 mm glucose <0.050 m Zn(NO3)2m Zn(NO3)2
Explanation:
The above aqueous solutions show that LiBr low boiling point followed by glucose and Zinc.
using the equation of boiling point elevation
ΔTb = i×Kb×M
Making temperature constant at a value of 290K you can simple do a calculation to conform the boiling point.
looking the van hoff values for Znc = 3 , LiBr = 2 and glucose = 1
(glucose)ΔTb = i×Kb×M = 1×290k×0.120 = 34.8
(Zinc) = 3×290×0.050 = 43.5
(LiBr) = 2×290×0.050 =29
∴ in conclusion LiBr has a the lowest decreasing boiling point
Based on the concentration of the solutions, the rank order of the solutions in terms of decreasing boiling point is 0.050 m LiBr < 0.120 mm glucose < 0.050 m Zn(NO3)2.
What is the boiling point of a liquid solution?
The boiling point of a liquid solution is the temperature at which the liquid begins to boil and change to vapor.
The concentration of each solution can be used to determine its boiling point.
Usng the equation of boiling point elevation:
- ΔTb = i × Kb × M
where:
- i is the Van’t Hoff factor
- Kb is the ebullioscopic constant
- m is the molality of the solute
The van hoff values for Zn(NO3)2 = 3 , LiBr = 2 and glucose = 1
Siince water is the solvent in all solutions,
Kb of water = 0.512 and boiling point of water = 100°C
Calculating the boiling point elevation:
For Glucose
ΔTb = 1 × 0.512 × 0.120 = 0.061°C
For Zn(NO3)2
ΔTb = 3 × 0.512 × 0.050 = 0.0768°C
For LiBr
ΔTb = 2 × 0.512 × 0.050 = 0.0512°C
LiBr elevates the boiling point of water the least.
Therefore, based on the concentration of the solutions, the rank order of the solutions in terms of decreasing boiling point is 0.050 m LiBr < 0.120 mm glucose < 0.050 m Zn(NO3)2.
Learn more about boiling point elevation at: https://brainly.com/question/4206205
