For this case we have that by definition, the equation of a line in the point-slope form is given by:
[tex]y-y_ {0} = m (x-x_ {0})[/tex]
Where:
[tex](x_ {0}, y_ {0}):[/tex]It is a point through which the line passes
m: It is the slope of the line
According to the graph we have that the line goes through the following points:
[tex](x_ {1}, y_ {1}) :( 4,2)\\(x_ {2}, y_ {2}): (- 2, -2)[/tex]
We found the slope:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-2-2} {- 2-4} = \frac {-4} {- 6} = \frac {2} {3}[/tex]
We choose a point:
[tex](x_ {0}, y_ {0}): (-2, -2)[/tex]
The equation of the line is:
[tex]y - (- 2) = \frac {2} {3} (x - (- 2))\\y + 2 = \frac {2} {3} (x + 2)[/tex]
ANswer:
[tex]y + 2 = \frac {2} {3} (x + 2)[/tex]
Option A