Question

A massless beam supports two weights as shown.
Find W such that the supporting force at
A is zero (static equilibrium). Force is 471 L' is L/3 and L'' is 9. Answer in nearest whole number.

Answer 1

The weight W = 471 N

Explanation:

Taking moments about B

N x L'' = W x L'

Here the moment is = force x perpendicular distance between the axis of rotation and the point of applied force .

Here L' = L/3 and L'' = 9

Thus from figure

471 x 9 = W x $\frac{L}{3}$

But L'' = $\frac{1}{2}$( L - $\frac{L}{3}$ ) = $\frac{L}{3}$ = 9

Thus W = 471 N

Answer 2

The value of the weight ( W ) is ; 471 N

Determine the weight ( W) value

First step : take moments about B

N * L" = W * L'

Where : L' = L/3,  L" = 9

From the figure

471 * 9 = W * $\frac{L}{3}$

also:

L" = 1/2 ( L - L/3 ) = L/3 = 9

Hence ; W = 471 N

Hence we can conclude that The value of the weight ( W ) is ; 471 N

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