Respuesta :
Answer : The balanced net ionic equation for the reactions are:
(A) [tex]2Ag^{+}(aq)+2Br^{-}(aq)\rightarrow AgBr(s)[/tex]
(B) [tex]H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)[/tex]
(C) [tex]Co^{2+}(aq)+S^{2-}(aq)\rightarrow CoS(s)[/tex]
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
Part A :
The balanced molecular equation will be,
[tex]2AgNO_3(aq)+MgBr_2(aq)\rightarrow Mg(NO_3)_2(aq)+2AgBr(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2Ag^+(aq)+2NO_3^{-}(aq)+Mg^{2+}(aq)+2Br^{-}(aq)\rightarrow Mg^{2+}(aq)+2NO_3^{-}(aq)+2AgBr(s)[/tex]
In this equation the species [tex]Mg^{2+}\text{ and }NO_3^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]2Ag^{+}(aq)+2Br^{-}(aq)\rightarrow AgBr(s)[/tex]
Part B :
The balanced molecular equation will be,
[tex]HClO_4(aq)+KOH(aq)\rightarrow H_2O(l)+KClO_4(aq)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]H^+(aq)+ClO_4^{-}(aq)+K^{+}(aq)+OH^{-}(aq)\rightarrow K^{+}(aq)+CLO_4^{-}(aq)+H_2O(l)[/tex]
In this equation the species [tex]K^{+}\text{ and }ClO_4^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)[/tex]
Part C :
The balanced molecular equation will be,
[tex](NH_4)_2S(aq)+CoCl_2(aq)\rightarrow 2NH_4Cl(aq)+CoS(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2NH_4^+(aq)+S^{2-}(aq)+Co^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2NH_4^{+}(aq)+2Cl^{-}(aq)+CoS(s)[/tex]
In this equation the species [tex]NH_4^{+}\text{ and }Cl^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Co^{2+}(aq)+S^{2-}(aq)\rightarrow CoS(s)[/tex]
The balanced net ionic equations are:
- A. Ag⁺(aq) + Br⁻(aq) ⇒ AgBr(s)
- B. H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)
- C. NH₄⁺(aq) + Cl⁻(aq) ⇒ NH₄Cl(s)
We want to write the balanced net ionic equations for the reactions that occur when the given aqueous solutions are mixed.
What is a net ionic equation?
A chemical equation in which only those ions undergoing chemical changes during the course of the reaction are represented.
A. silver nitrate, AgNO₃, and magnesium bromide, MgBr₂.
Ag⁺(aq) + Br⁻(aq) ⇒ AgBr(s)
NO₃⁻ and Mg²⁺ are not in the net ionic equation because they are spectator ions.
B. perchloric acid, HClO₄, and potassium hydroxide, KOH.
H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)
ClO₄⁻ and K⁺ are not in the net ionic equation because they are spectator ions.
C. ammonium sulfide, (NH₄)₂S, and cobalt(II) chloride, CoCl₂
NH₄⁺(aq) + Cl⁻(aq) ⇒ NH₄Cl(s)
S²⁻ and Co²⁺ are not in the net ionic equation because they are spectator ions.
The balanced net ionic equations are:
- A. Ag⁺(aq) + Br⁻(aq) ⇒ AgBr(s)
- B. H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)
- C. NH₄⁺(aq) + Cl⁻(aq) ⇒ NH₄Cl(s)
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