Answer:
the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s
Explanation:
given information
car's mass, m = 1200 kg
[tex]h_{A}[/tex] = 100 m
[tex]v_{A}[/tex] = [tex]v_{A}[/tex]
[tex]h_{B}[/tex] = 150 m
[tex]v_{B}[/tex] = 0
according to conservative energy
the distance from point A to B, h = 150 m - 100 m = 50 m
the initial speed [tex]v_{A}[/tex]
final speed [tex]v_{B}[/tex] = 0
thus,
[tex]v_{B}[/tex]² = [tex]v_{A}[/tex]² - 2 g h
0 = [tex]v_{A}[/tex]² - 2 g h
[tex]v_{A}[/tex]² = 2 g h
[tex]v_{A}[/tex] = √2 g h
= √2 (9.8) (50)
= 31.3 m/s