A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0? Neglect friction.

Respuesta :

Answer:

the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s

Explanation:

given information

car's mass, m = 1200 kg

[tex]h_{A}[/tex] = 100 m

[tex]v_{A}[/tex] = [tex]v_{A}[/tex]

[tex]h_{B}[/tex] = 150 m

[tex]v_{B}[/tex] = 0

according to conservative energy

the distance from point A to B, h = 150 m - 100 m = 50 m

the initial speed [tex]v_{A}[/tex]

final speed  [tex]v_{B}[/tex] = 0

thus,

[tex]v_{B}[/tex]² = [tex]v_{A}[/tex]² - 2 g h

0 = [tex]v_{A}[/tex]² - 2 g h

[tex]v_{A}[/tex]² = 2 g h

[tex]v_{A}[/tex] = √2 g h

    = √2 (9.8) (50)

    = 31.3 m/s