Question

Nana manages to stop their decent. While stopped, with the axe in the ice, her coefficient of static friction is LaTeX: \mu_s=2.8μ s = 2.8. What is the maximum acceleration ice Popo can climb up the rope, without causing them to slide again?

Answer 1

Answer:

Acceleration, a= 1.65m/s^2

Acceleration is downward.

Explanation:

y: N- m1gcosalpha=0

x: Ff- FT- m1gsinalpha= m1× alpha

Ff= uN= um1gcosalpha

FT=m2g

Acceleration ,a = g(ucosalpha- (m2/m1)-sin alpha)

a= (m2/m1) + sinalpha= 1.976

Cos alpha= 0.766

U2= 2.8

a= g(2.8×0.766)- 1.976)

a= g× 0.1688

a= 9.8× 0.1688

a=1.65m/s^2