Respuesta :
Answer:
The average time spent waiting in line for each student is 2.25 students.
Explanation:
Use Lq with a single server formula.
λ = Avg arrival rate = 15 std/hr
μ= Avg server rate (individual server capacity) = 20 std/hr
Μ = # of servers/line (identical capacities)
= λ[tex]^{2}[/tex]/μ(μ- λ)
=15[tex]^{2}[/tex] / 20(20-15)
= 225/100
=2.25 students.
There are different kinds of calculations as regards to time. Note that average service rate increases, the shape of the negative exponential distribution of service times often is known to be less gently curved as it moves ever closer to the graph start up point.
Therefore , The average time spent waiting in line for each student is 2.25 students.
This calculated by:
λ refers to Avg arrival rate. This is denoted as
= 15 std/hr
μ refers to as Avg server rate. This is individual server capacity. It is denoted as
= 20 std/hr
Μ is known as number of servers/line or simply say identical capacities.
Therefore = λ/μ(μ- λ)
Input or fill up all numbers (values) into the equation above;
=15 / 20(20-15)
= 225/100
=2.25
Conclusively, The average time spent waiting in line for each student is 2.25 students.
See full options below
What is the average time spent waiting in line for each
student? What is the average number of students in the line?
a. 2.25 students
b. 5 students
c. 15 students
d. 20 students
Learn more about average time from
https://brainly.com/question/4931057