Respuesta :

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{9})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{2}) \\\\\\ y-9=\cfrac{3}{2}x-3\implies y=\cfrac{3}{2}x+6[/tex]