Answer:
0.50
Step-by-step explanation:
Given that a box contains three coins: two regular and one fake one-sided coin (P(H) = 1) You pick a coin at random and toss it.
Probability of selecting any one coin = 1/3
The coins are regular 1, regular 2 , fake
P for head 0.5 0.5 1
Probability for head = [tex]\frac{1}{3} (1+0.5+0.5) = 0.6667[/tex]
using total probability theorem for mutually exclusive and exhaustive)
Probability that coin is not fake/head = [tex]\frac{0.5+0.5}{1+0.5+0.5} \\= 0.5[/tex]