Question

The chemical formula for beryllium sulfide is BeS. A chemist measured the amount of beryllium sulfide produced during an experiment. She finds that 8.31 g of beryllium sulfide is produced. Calculate the number of moles of beryllium sulfide produced. Be sure your answer has the correct number of significant digits

Answer 1

Answer:

The answer is 0.20231 mol BeS

Explanation:

we look for the molecular weight of beryllium and sulfur in the periodic table:

molecular weight of Be = 9.01 g/mol

molecular weight of S = 32.065 g/mol

therefore, the molecular weight of beryllium sulfide is equal to:

molecular weight of BeS = 9.01 + 32.065 = 41.075 g/mol

The number of moles will be equal to:

$n BeS = 8.31 g BeS x\frac{1 mol BeS}{41.075 g BeS}=0.20231 mol BeS$