Question

You collect 100 samples from a large butterfly population. Fifty specimens are dark brown, 20 are speckled, and 30 are white. Coloration in this species of butterfly is controlled by one gene locus: BB individuals are brown, Bb are speckled, and bb are white. What are the allele frequencies for the coloration gene in this population

Answer 1

Answer:

Total Allele: 100

BB = 100 ;  Bb = 40 ;  bb = 60

$\rho = 0.6\\\delta = 0.4$

Step-by-step explanation:

There are two allele in each gene. Since we have 100 samples of butterfly genes, the total number of allele are 100 x 2 = 200.

For each species:

Dark Brown (BB) → 50 x 2 = 100 allele

Speckled (Bb) → 20 x 2 = 40 allele

White (bb) → 30 x 2 = 60 allele

So, if we let $\rho$ be the frequency of the B allele and $\delta$ be the frequency of the b alleles, then:

$\rho = \frac{ ((50 \times 2) + 20)}{200} \\\ \\\rho = \frac{100+20}{200} = \frac{120}{200}\\\\\\rho = 0.6$

$\delta = \frac{((30 x 2) + 20)}{200}\\\\\delta = \frac{60+20}{200} = \frac{80}{200}\\\\\delta = 0.4$

Answer 2

We want to get the allele frequencies for the coloration gene in the population of butterflies, we will get:

• The frequency for BB (brown) is 50%
• The frequency for Bb (speckled) is 20%
• The frequency for bb (white) is 30%

How to get the frequencies?

Assuming that the sample is a good representation of the butterfly population, the frequencies are just given by the quotient between the number of each type of butterflies and the total number of butterflies in the sample, times 100%.

There are 100 butterflies, 50 are dark brown, 20 are speckled, and 30 are white.

The frequency for BB (brown) is:

$F_{BB} = (50/100)*100\% = 50\%$

The frequency for Bb (speckled) is:

 $F_{Bb} = (20/100)*100\% = 20\%$

The frequency for bb (white) is:

$F_{bb} = (30/100)*100\% = 30\%$

If you want to learn more about frequencies, you can read:

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