Question

A box is moved 10 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N force acting parallel to the floor in the direction of motion and a 5 N force acting perpendicular to the floor. The work done is

Answer 1

Answer:

Work done = 100 J

Explanation:

Given:

Distance moved by the box (d) = 10 m

Parallel force acting on it $(F_1)$ = 10 N

Perpendicular force acting on it $(F_2)$ = 5 N

Work done is the product of force and displacement along the line of action of force.

So, the perpendicular force doesn't do any work and it's only the parallel force that does work as the displacement caused is along the parallel force direction.

So, work done is given as:

$Work=F_1\times d\\\\Work=10\ N \times 10\ m \\\\W=100\ J$

Therefore, work done is 100 J.