Question

The velocity of a particle which moves along the s-axis
is given by s=40-3t^2 where t is in seconds.
Calculate the displacement delta s of the particle during
the interval from t=2 to t=4

Answer 1

Answer:

24 units

Explanation:

Δs = ∫ v(t) dt

Δs = ∫₂⁴ (40 − 3t²) dt

Δs = (40t − t³) |₂⁴

Δs = (40(4) − (4)³) − (40(2) − (2)³)

Δs = (160 − 64) − (80 − 8)

Δs = 96 − 72

Δs = 24