Answer:
[tex] P(X=7)[/tex]
[tex]P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}[/tex]
Where N=15 is the population size, M=12 is the number of success states in the population, n=7 is the number of draws, k is the number of observed successes
And using the probability mass function we got:
[tex]P(X=7)= \frac{(12C7)(15-12 C 7-7)}{15C7}=\frac{792*1}{6435}=0.123[/tex]
So then the answer for this case would be 0.123.
Step-by-step explanation:
Previous concepts
The hypergeometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:
[tex]P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}[/tex]
Where N=15 is the population size, M=12 is the number of success states in the population, n=7 is the number of draws, k is the number of observed successes
The expected value and variance for this distribution are given by:
[tex]E(X)= n\frac{M}{N}[/tex]
[tex]Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}[/tex]
Solution to the problem
For this case we want this probability:
[tex] P(X=7)[/tex]
And using the probability mass function we got:
[tex]P(X=7)= \frac{(12C7)(15-12 C 7-7)}{15C7}=\frac{792*1}{6435}=0.123[/tex]
So then the answer for this case would be 0.123.