Question

A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet The pendulum has a length of 2 m and its period is measured to be 2 s. The value of g obtained in this investigation is most nearly :A. 1 m/s2 B. 2 m/s2C. 5 m/s2 D. 10 m/s2 E. 20 m/s2

Answer 1

Answer:

E. 20 m/s^2

Explanation:

The period of a pendulum is given by the following equation:

$T = 2 * pi * \sqrt{\frac{L}{g} }$

Where T = time period (in seconds)

L = length of pendulum

and g = acceleration due to gravity

Substituting the values from the question we get:

$2 = 2 * pi *\sqrt{\frac{2}{g} }$

Solving for g, we get:

g = 19.74 m/s^2

Closest option to this is option (E).