Respuesta :
Answer:
b) between 18.4 and 31.6 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 25, \sigma = 4[/tex]
Middle 90%
Lower bound: Value of X when Z has a pvalue of 0.5 - 0.9/2 = 0.05.
Upper bound: Value of X when Z has a pvalue of 0.5 + 0.9/2 = 0.95.
Lower bound:
X when Z = -1.645
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.645 = \frac{X - 25}{4}[/tex]
[tex]X - 25 = -1.645*4[/tex]
[tex]X = 18.42[/tex]
Upper bound
X when Z = 1.645
[tex]1.645 = \frac{X - 25}{4}[/tex]
[tex]X - 25 = 1.645*4[/tex]
[tex]X = 31.58[/tex]
So the correct answer is:
b) between 18.4 and 31.6 minutes.
For a simple haircut, the middle 90 percent of the customers will require between 18.4 and 31.6 minutes.
So, Option (b) is correct.
Normal distribution is a continuous probability distribution where values lie in a symmetrical fashion mostly situated around the mean.
Here, we use Z score rule in normally distribution.
Let us assume that mean is [tex]\mu[/tex] and standard deviation is [tex]\sigma[/tex] and X is measure of variable.
So, [tex]Z=\frac{X-\mu}{\sigma}[/tex]
Given that, mean = 25 and deviation = 4
Now we have to find lower bound value of variable X when Z = -1.645
[tex]-1.645=\frac{X-25}{4}\\\\X=18.42[/tex]
Now we have to find upper bound value of variable X when Z = 1.645
[tex]1.645=\frac{X-25}{4}\\\\X=31.58[/tex]
Since, value of variable X is between 18.42 and 31.58.
Therefore, For a simple haircut, the middle 90 percent of the customers will require between 18.4 and 31.6 minutes.
Thus, option (b) is correct.
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