Question

In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of +e) flow through a cross-sectional area each second. What is the current in the tube?

Answer 1

Answer:

current in the tube is 0.6A

Explanation:

Charged particles move in opposite directions, thus their contributions to total current are additive.

I = (3 × 10¹⁸ + 0.75 × 10¹⁸) * (1.6 × 10⁻¹⁹)

I = 0.6A

Answer 2

The current in the tube is 0.6A

Calculation of the current:

Since In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of +e)

Since Charged particles move in opposite directions, so their contributions to total current are additive.

Now the current is

I = (3 × 10¹⁸ + 0.75 × 10¹⁸) * (1.6 × 10⁻¹⁹)

I = 0.6A

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