Question

At a particular temperature, an equilibrium mixture the reaction below was found to contain 0.747 atm of I2, 0.724 atm of H2 and 5.59 atm of HI. Calculate the value of the equilibrium constant, Kp at this temperature. H2(g) + I2(g) <=> 2 HI(g)

Answer 1

Answer:

57.78

Explanation:

The question asks to calculate the equilibrium constant value Kp at a particular temperature.

To do this, we firstly need to write the correct expression for the equilibrium constant. We do this as follows;

Kp = [HI]^2/([I2][H2]

Kp = (5.59)^2/(0.747*0.724)

Kp = 31.2481/0.5408

Kp = 57.78