Question

A pedestrian moves 6.00 km east then 13.0 km north. Using the graphical method, find the magnitude and direction of the resultant displacement vector.

Answer 1

Resultant vector
r = (6^2 + 13^2)^0.5
r = (36 + 169)^0.5
r = 205^0.5
r = 14.13 km

Direction of the vector
tan theta = 13/6
tan theta = 2.17
theta = 65.22