Respuesta :
Answer:Pois(ln(200))
Step-byy-step explanation:
Let N be the number of received calls in a day
That is
N∼Pois(λ).
0.5% = 0.5/100 = 1/200 of no calls
P(N=0)=e^−λ=1/200
-λ=e^(1/200)
λ=in(200)
Our number of calls in a day is distributed Pois(ln(200)).
Answer:
Number of calls in a day is distribution pois(ln(200)
Step-by-step explanation:
Let X be the number of received calls in a day, I.e X~poisX
P(X=0)=e~^=1/200 =^.our=in(200)