Question

From a group of 8 people, including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that the 3 people selected will include George but not Nina?A. 5/56
B. 9/56
C. 15/56
D. 21/56
E. 25/56

Answer 1

Answer:

Therefore, the probability is P=15/56.

Step-by-step explanation:

We know that from a group of 8 people, including George and Nina, 3 people are to be selected at random to work on a certain project.

We calculate the number of possible combinations, to choose from 8 people 3.

$C_3^8=\frac{8!}{3!(8-3)!}=56$

How George has to be on the team while Nina can't be on the team. It remains for us to choose 2 people from the remaining 6 people.

$C_2^6=\frac{6!}{2!(6-2)!}=15$

Therefore, the probability is P=15/56.