Answer:
Question 4: The minor arc is AB and has a measure of 115°.
Question 5: [tex]15\pi\: m[/tex]
Question 6: The area of the figure is [tex]70.6in^2[/tex]
Question 7: [tex]-5.934\: \text{radians.}[/tex]
Question 8: [tex]-30^o[/tex]
Step-by-step explanation:
Question 4:
The minor arc of the circle that subtends the least degrees, and for this circle it is AB and has a measure of 115°.
Question 5:
The length [tex]L[/tex] of the arc of the circle with a radius [tex]R[/tex] subtending [tex]\theta[/tex] radians is
[tex]L = \theta R[/tex]
The arc YPX measures 360° - 90° = 270, which is [tex]\dfrac{3}{2}\pi[/tex]; therefore,
[tex]L = \dfrac{3}{2}\pi *10[/tex]
[tex]\boxed{L = 15\pi \:m }[/tex]
Question 6:
We first need to find what percent of the circle the figure is.
165° is
[tex]\dfrac{165}{360} *100\% = 45.83\%[/tex]
percent of 360°.
Therefore, the area of the figure must also be 45.83% of the area of the circle. The area of the circle is
[tex]A = \pi (7)^2\\A = 153.94in^2[/tex]
therefore, the are of the figure is
[tex]A_{seg} = 153.94*45.83\% \\\\\boxed{A_{seg} = 70.6in^2}[/tex]
Question 7:
One radian is 57.296°; therefore, -340° in radians is
[tex]\dfrac{-340^o}{57.296^o} = -5.934\: \text{radians.}[/tex]
Question 8:
One radian is 57.296°; therefore, [tex]\dfrac{-\pi }{6}[/tex] radians in degrees is
[tex]\dfrac{-\pi }{6}*57.296^o = -30^o[/tex]