Respuesta :

Answer:

Question 4:  The minor arc is AB and has a measure of 115°.

Question 5: [tex]15\pi\: m[/tex]

Question 6: The area of the figure is [tex]70.6in^2[/tex]

Question 7: [tex]-5.934\: \text{radians.}[/tex]

Question 8: [tex]-30^o[/tex]

Step-by-step explanation:

Question 4:

The minor arc of the circle that subtends the least degrees, and for this circle it is AB and has a measure of 115°.

Question 5:

The length [tex]L[/tex] of the arc of the circle with a radius [tex]R[/tex] subtending [tex]\theta[/tex] radians is

[tex]L = \theta R[/tex]

The arc YPX measures 360° - 90° = 270, which is [tex]\dfrac{3}{2}\pi[/tex]; therefore,

[tex]L = \dfrac{3}{2}\pi *10[/tex]

[tex]\boxed{L = 15\pi \:m }[/tex]

Question 6:

We first need to find what percent of the circle the figure is.

165° is

[tex]\dfrac{165}{360} *100\% = 45.83\%[/tex]

percent of 360°.

Therefore, the area of the figure must also be 45.83% of the area of the circle. The area of the circle is  

[tex]A = \pi (7)^2\\A = 153.94in^2[/tex]

therefore, the are of the figure is

[tex]A_{seg} = 153.94*45.83\% \\\\\boxed{A_{seg} = 70.6in^2}[/tex]

Question 7:

One radian is 57.296°; therefore, -340° in radians is

[tex]\dfrac{-340^o}{57.296^o} = -5.934\: \text{radians.}[/tex]

Question 8:

One radian is 57.296°; therefore, [tex]\dfrac{-\pi }{6}[/tex] radians in degrees is

[tex]\dfrac{-\pi }{6}*57.296^o = -30^o[/tex]