Question

In which of the compounds below is there more than one kind of hybridization (sp, sp2, sp3) for carbon? I. CH 3CH 2CH 2CH 3 II. CH 3CH = CHCH 3 III. CH 2 = CH – CH = CH 2 IV. H – C ≡ C – H

Answer 1

The compounds containing more than one kind of hybridization (sp, sp2, sp3) for carbon is CH3CH = CHCH3.

Explanation:

• Orbital hybridization is the idea of blending nuclear orbitals into new hybrid orbitals reasonable for the matching of electrons to form chemical bonds in the valence bond hypothesis.  

Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.  

• In sp – Hybridisation 1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals, having a straight structure.  In sp2 – Hybridisation   1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals, having a planar triangular structure.  In  sp3 – Hybridisation  1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals having a tetrahedral structure.

Answer 2

The compound in which there is more than one kind of hybridization (sp, sp2, sp3) for carbon is; Choice II. CH3 CH = CH CH 3 (with sp2 and sp3 hybridization)

Hybridization of orbitals is characterized by the blending of nuclear orbitals in a bid to form new hybrid orbitals whose objective is the matching of electrons to form chemical bonds in the valency bond hypothesis.

Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.

• In sp – Hybridisation: the structure is usually linear since 1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals.

• In sp2 – Hybridisation: The structure is usually a planar triangular structure. 1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals.

• In sp3 – Hybridisation: The structure is usually tetrahedral since 1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals.

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