The given statement is false because it isn't an empty set!
Step-by-step explanation:
We have following sets of inequalities:
[tex]4x+5=13\\4x+5>13\\4x+5<13\\[/tex]
From [tex]4x+5=13[/tex] we get ,
[tex]4x = 8 \\x=2[/tex]
Therefore solution set is x=2.
Now, for [tex]4x+5>13[/tex] we get ,
[tex]4x+5>13 \\4x>8\\x>2[/tex]
Therefore solution set is x>2.
For [tex]4x+5<13[/tex] we get ,
[tex]4x+5<13\\4x<8\\x<2\\[/tex]
Therefore solution set is x<2.
Now, the union of x=2, x<2 & x>2 is -∞<x<∞. i.e. all possible values of x. And so above statement is false because it isn't an empty set!