Question

What is the head loss for water flowing through a horizontal pipe if the gage pressure at point 1 is 1.05 kPa, the gage pressure at point 2 downstream is 1.00 kPa, and the velocity is constant?

Answer 1

Answer:

The required head loss is 0.00509 m.

Explanation:

Head loss for horizontal pipe  (zout − zin) with no pump (hs = 0), and constant cross section  (Vout =Vin) is given by:

                  Head loss= $\frac{P_{1}- P_{2} }{dg}$                     ( for constant velocity)

where,

$P_{1}$  = pressure at point 1.

$P_{2}$ = pressure at point 2.

d= density of water flowing

g = acceleration due to gravity

Now,

                                             Head loss = $\frac{(1.05 - 1) }{1 * 9.81}$

                                                              = 0.00509 m

Hence the head loss is 0.00509 m.