Answer:
The magnitude of the induced e.m.f is 571 mV
Explanation:
Given;
magnetic field strength, B = 0.4T
area of the loop, A = 1m²
time = 0.7s
Since the angle of inclination of the magnetic field, then the direction of the induced e.m.f, θ = 0
According to faraday's law; the induced emf is directly proportional to the rate of change of flux.
Thus, magnitude of the induced e.m.f is given as
[tex]E.M.F = \frac{\delta \phi}{\delta t} \\\\\phi = BAcos \theta = BAcos0 = BA\\\\E.M.F = \frac{0.4 X1}{0.7} = 0.571 V[/tex]