Question

Determine the value of Kp for the following reaction if the equilibrium concentrations are as follows: P(NOCl)eq = 0.22 atm, P(NO)eq = 0.10 atm, P(Cl2)eq = 0.081 atm. 2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)

Answer 1

Answer:

Kp = 0,017

Explanation:

The equilibrium constant, Kp is defined as the ratio of product and reactant concentrations at equilibrium in terms of partial pressures.

In the reaction:

2NOCl(g) ⇌ 2NO(g) + Cl₂(g) Kp is defined as:

Kp = P[NO]² P[Cl₂] / P[NOCl]²

Replacing:

Kp = [0,10]² [0,081] / [0,22]²

Kp = 0,017

I hope it helps!