Answer: 0.00995
Explanation: The Hardy-Weinberg
theorem states that:
1. allele frequencies in a population will not change from generation to generation.
2. if the allele frequencies in a population with two alleles at a locus are p and q, then the expected genotype frequencies are P², 2pq, and q². For a population in genetic equilibrium:
p + q = 1.0
Where
p = the frequency of the dominant allele
q = the frequency of the recessive allele
Therefore
p² + 2pq + q² = 1
Where
p² = frequency of AA (homozygous dominant)
2pq = frequency of Aa (heterozygous)
q² = frequency of aa (homozygous recessive)
To get the frequency of frequency of heterozygotes in a population of green anoles,
p + q = 1.0
P= 0.005
q= ?
Therefore
q= 1 - P
q= 1 - 0.005
q= 0.995.
Therefore, the frequency of heterozygotes in a population of green anoles is 2Pa
Where P = 0.005
q= 0.99
Frequency of heterozygotes is
2Pa= 2 x 0.005 x 0.995
= 0.00995(five decimal)
