nandhy
nandhy
02-07-2016
Mathematics
contestada
3r(2p-5)-p(2p-5) factorise it
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toporc
toporc
02-07-2016
3r(2p - 5) - p(2p - 5)
The common factor is (2p - 5), therefore we can write:
(2p - 5)(3r - p)
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olemakpadu
olemakpadu
02-07-2016
3r(2p - 5) - p(2p - 5)
let a = 2p - 5
3r(2p - 5) - p(2p - 5) = 3ra - pa = a(3r - p)
let's substitute back the value of a.
a(3r - p) = (2p - 5)(3r - p)
Therefore: 3r(2p - 5) - p(2p - 5) = (2p - 5)(3r - p)
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