Question

For each of the following reactions, write the appropriate equilibrium equation. (Equilibrium expressions take the general form: Keq = [C]c / [A]a . [B]b. Subscripts and superscripts that include letters must be enclosed in braces {}.) (a) CH3COOH(aq) equilibrium reaction arrow CH3COO−(aq) + H +(aq)

Answer 1

Answer:

The equilibrium constant expression will be:

$K_{eq}=\frac{[CH_COO^-]^1[H^+]^1}{[CH_3COOH]^1}$

Explanation:

The equilibrium constant is defined as ratio of concentration of products to the concentration of the reactants raised to their respective stoichiometric coefficients appearing the chemical equation.

$aA+bB\rightleftharpoons cC$

$K_{eq}=\frac{[C]^c}{[A]^a[B]^b}$

$CH3COOH(aq)\rightleftharpoons CH3COO^-(aq) + H^+(aq)$

So, the equilibrium constant expression will be:

$K_{eq}=\frac{[CH_COO^-]^1[H^+]^1}{[CH_3COOH]^1}$