Answer:
Number of lead atoms per cubic meter [tex]3.299\times 10^{28}[/tex]
Explanation:
Density of lead is [tex]11.35g/cm^{3}[/tex] means mass of [tex]1cm^{3}[/tex] lead is 11.35 g
11.35 g of lead = [tex]\frac{11.35}{207.2}mol[/tex] of lead = 0.05478 mol of lead
[tex]1cm^{3}=1\times 10^{-6}m^{3}[/tex]
[tex]1mol=6.023\times 10^{23}[/tex] number of particles
So, 0.05478 mol of lead = [tex](0.05478\times 6.023\times 10^{23})[/tex] number of atoms of lead
= [tex]3.299\times 10^{22}[/tex] number of atoms of lead
So, number of lead atoms per cubic meter = [tex]\frac{3.299\times 10^{22}}{1\times 10^{-6}}=3.299\times 10^{28}[/tex]