Question

Determine the molar concentration of ammonium ions, NH4 , in a solution that results when 4.53 g of (NH4)2SO4 are dissolved in 100 mL of water.

Answer 1

Answer:

Molar concentration of solution is 0.343 M

Explanation:

Molar mass of $(NH_{4})_{2}SO_{4}$ is 132.14 g/mol

So, 4.53 g of $(NH_{4})_{2}SO_{4}$ = $\frac{4.53}{132.14}mol$ of $(NH_{4})_{2}SO_{4}$ = 0.0343 mol of $(NH_{4})_{2}SO_{4}$

Molar concentration means how many moles of solute are present in 1000 mL of solution

Here solute is $(NH_{4})_{2}SO_{4}$

Let's assume total volume of solution is equal to volume of water as solids have negligible volume with respect to liquid

So, molar concentration of solution = $\frac{0.0343\times 1000}{100}M=0.343M$

Answer 2

Following are the calculation to the molar concentration:  

 Molar mass:

$\to (NH_4)_2SO_4\ = \ 132.14 \ \frac{g}{mol}$

So,

$\to 4.53 \ g \times (NH_4)_2SO_4 \\\\\to \frac{4.53}{132.14} \ mol \times (NH_4)_2SO_4 \\\\ \to 0.0343\ mol \ of (NH_4)_2SO_4$

The number of moles of solute present in $1000 \ mL$ of solution is referred to as the molar concentration.

Solute = $(NH_4)_2SO_4$

Suppose that the entire volume of the solution equals the volume of water because solids have little volume in comparison to liquids.

Calculating the molar concentration of the solution:

$= \frac{0.0343 \times 1000}{100}\ M \\\\ = 0.0343 \times 10\ M \\\\= 0.343\ M$

Therefore, the molar concentration of the solution is "0.343 M"

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