Answer:
a) 3654.5 joules per cycle is rejected to the reservoir at 300 K by the Carnot Engine.
b) Mechanical work performed by the engine during each cycle = 3045.5 J = 3.046 KJ
Explanation:
For a Carmot engine,
(Q꜀/T꜀) + (Qₕ/Tₕ) = 0
(Q꜀/T꜀) = - (Qₕ/Tₕ)
Q꜀ = - T꜀ × (Qₕ/Tₕ)
Qₕ = 6.70 KJ
Tₕ = 550 K
Q꜀ = ?
T꜀ = 300 K
Q꜀ = - 300 (6700/550) = - 3654.5 J = - 3.65 KJ
b) Mechanical work done by the Carnot engine is given by
W = |Qₕ| - |Q꜀| = 6700 - 3654.5 = 3045.5 J